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5(2+x)-x=10+4(x+4)
We move all terms to the left:
5(2+x)-x-(10+4(x+4))=0
We add all the numbers together, and all the variables
5(x+2)-x-(10+4(x+4))=0
We add all the numbers together, and all the variables
-1x+5(x+2)-(10+4(x+4))=0
We multiply parentheses
-1x+5x-(10+4(x+4))+10=0
We calculate terms in parentheses: -(10+4(x+4)), so:We add all the numbers together, and all the variables
10+4(x+4)
determiningTheFunctionDomain 4(x+4)+10
We multiply parentheses
4x+16+10
We add all the numbers together, and all the variables
4x+26
Back to the equation:
-(4x+26)
4x-(4x+26)+10=0
We get rid of parentheses
4x-4x-26+10=0
We add all the numbers together, and all the variables
-16!=0
There is no solution for this equation
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