5(2+y)-4=10+4(y+1)

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Solution for 5(2+y)-4=10+4(y+1) equation:



5(2+y)-4=10+4(y+1)
We move all terms to the left:
5(2+y)-4-(10+4(y+1))=0
We add all the numbers together, and all the variables
5(y+2)-(10+4(y+1))-4=0
We multiply parentheses
5y-(10+4(y+1))+10-4=0
We calculate terms in parentheses: -(10+4(y+1)), so:
10+4(y+1)
determiningTheFunctionDomain 4(y+1)+10
We multiply parentheses
4y+4+10
We add all the numbers together, and all the variables
4y+14
Back to the equation:
-(4y+14)
We add all the numbers together, and all the variables
5y-(4y+14)+6=0
We get rid of parentheses
5y-4y-14+6=0
We add all the numbers together, and all the variables
y-8=0
We move all terms containing y to the left, all other terms to the right
y=8

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