5(2+y)-y=2(y+1)

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Solution for 5(2+y)-y=2(y+1) equation:



5(2+y)-y=2(y+1)
We move all terms to the left:
5(2+y)-y-(2(y+1))=0
We add all the numbers together, and all the variables
5(y+2)-y-(2(y+1))=0
We add all the numbers together, and all the variables
-1y+5(y+2)-(2(y+1))=0
We multiply parentheses
-1y+5y-(2(y+1))+10=0
We calculate terms in parentheses: -(2(y+1)), so:
2(y+1)
We multiply parentheses
2y+2
Back to the equation:
-(2y+2)
We add all the numbers together, and all the variables
4y-(2y+2)+10=0
We get rid of parentheses
4y-2y-2+10=0
We add all the numbers together, and all the variables
2y+8=0
We move all terms containing y to the left, all other terms to the right
2y=-8
y=-8/2
y=-4

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