5(2-2y)9y=2-19y

Solution for 5(2-2y)9y=2-19y equation:

5(2-2y)9y=2-19y

We move all terms to the left:

5(2-2y)9y-(2-19y)=0

We add all the numbers together, and all the variables

5(-2y+2)9y-(-19y+2)=0

We multiply parentheses

-90y^2+90y-(-19y+2)=0

We get rid of parentheses

-90y^2+90y+19y-2=0

We add all the numbers together, and all the variables

-90y^2+109y-2=0

a = -90; b = 109; c = -2;
Δ = b2-4ac
Δ = 1092-4·(-90)·(-2)
Δ = 11161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(109)-\sqrt{11161}}{2*-90}=\frac{-109-\sqrt{11161}}{-180}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(109)+\sqrt{11161}}{2*-90}=\frac{-109+\sqrt{11161}}{-180}
$