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5(2-3q)/4(3+4q)=-50
We move all terms to the left:
5(2-3q)/4(3+4q)-(-50)=0
Domain of the equation: 4(3+4q)!=0We add all the numbers together, and all the variables
q∈R
5(-3q+2)/4(4q+3)-(-50)=0
We add all the numbers together, and all the variables
5(-3q+2)/4(4q+3)+50=0
We multiply all the terms by the denominator
5(-3q+2)+50*4(4q+3)=0
We multiply parentheses
-15q+50*4(4q+3)+10=0
Wy multiply elements
-15q+200q(4+10=0
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