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5(2-3x^2)-6=14
We move all terms to the left:
5(2-3x^2)-6-(14)=0
We add all the numbers together, and all the variables
5(2-3x^2)-20=0
We multiply parentheses
-15x^2+10-20=0
We add all the numbers together, and all the variables
-15x^2-10=0
a = -15; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·(-15)·(-10)
Δ = -600
Delta is less than zero, so there is no solution for the equation
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