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5(2-4(y-1))=5(2y+9)
We move all terms to the left:
5(2-4(y-1))-(5(2y+9))=0
We calculate terms in parentheses: -(5(2y+9)), so:We get rid of parentheses
5(2y+9)
We multiply parentheses
10y+45
Back to the equation:
-(10y+45)
5(2-4(y-1))-10y-45=0
We add all the numbers together, and all the variables
-10y+5(2-4(y-1))-45=0
We move all terms containing y to the left, all other terms to the right
-10y+5(2-4(y-1))=45
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