5(2-b)+10(b-2)-2(2.5b+5)=3(3b-15)

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Solution for 5(2-b)+10(b-2)-2(2.5b+5)=3(3b-15) equation: 



5(2-b)+10(b-2)-2(2.5b+5)=3(3b-15)

We move all terms to the left:

5(2-b)+10(b-2)-2(2.5b+5)-(3(3b-15))=0

We add all the numbers together, and all the variables

5(-1b+2)+10(b-2)-2(2.5b+5)-(3(3b-15))=0

We multiply parentheses

-5b+10b-4b-(3(3b-15))+10-20-10=0



We calculate terms in parentheses: -(3(3b-15)), so:

3(3b-15)

We multiply parentheses

9b-45

Back to the equation:

-(9b-45)



We add all the numbers together, and all the variables

b-(9b-45)-20=0

We get rid of parentheses

b-9b+45-20=0

We add all the numbers together, and all the variables

-8b+25=0

We move all terms containing b to the left, all other terms to the right

-8b=-25

b=-25/-8

b=3+1/8

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