5(2-c)-3(4-2c)=20

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Solution for 5(2-c)-3(4-2c)=20 equation: 


Simplifying
5(2 + -1c) + -3(4 + -2c) = 20
(2 * 5 + -1c * 5) + -3(4 + -2c) = 20
(10 + -5c) + -3(4 + -2c) = 20
10 + -5c + (4 * -3 + -2c * -3) = 20
10 + -5c + (-12 + 6c) = 20

Reorder the terms:
10 + -12 + -5c + 6c = 20

Combine like terms: 10 + -12 = -2
-2 + -5c + 6c = 20

Combine like terms: -5c + 6c = 1c
-2 + 1c = 20

Solving
-2 + 1c = 20

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 1c = 20 + 2

Combine like terms: -2 + 2 = 0
0 + 1c = 20 + 2
1c = 20 + 2

Combine like terms: 20 + 2 = 22
1c = 22

Divide each side by '1'.
c = 22

Simplifying
c = 22

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