5(2-c)/2=-2(2c+3)/3

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Solution for 5(2-c)/2=-2(2c+3)/3 equation: 



5(2-c)/2=-2(2c+3)/3

We move all terms to the left:

5(2-c)/2-(-2(2c+3)/3)=0

We add all the numbers together, and all the variables

5(-1c+2)/2-(-2(2c+3)/3)=0

We calculate fractions


(-5c)/()+(-(-2(2c+3)*2)/()=0



We calculate terms in parentheses: +(-(-2(2c+3)*2)/(), so:

-(-2(2c+3)*2)/(

We multiply all the terms by the denominator


-(-2(2c+3)*2)



We calculate terms in parentheses: -(-2(2c+3)*2), so:

-2(2c+3)*2

We multiply parentheses

-8c-12

Back to the equation:

-(-8c-12)



We get rid of parentheses

8c+12

Back to the equation:

+(8c+12)



We get rid of parentheses

(-5c)/()+8c+12=0

We multiply all the terms by the denominator


(-5c)+8c*()+12*()=0

We add all the numbers together, and all the variables

(-5c)+8c*()=0

We get rid of parentheses

-5c+8c*()=0

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