5(2-r)=35

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Solution for 5(2-r)=35 equation: 



5(2-r)=35

We move all terms to the left:

5(2-r)-(35)=0

We add all the numbers together, and all the variables

5(-1r+2)-35=0

We multiply parentheses

-5r+10-35=0

We add all the numbers together, and all the variables

-5r-25=0

We move all terms containing r to the left, all other terms to the right

-5r=25

r=25/-5

r=-5

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