5(2-u)-u=10+4(u+1)

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Solution for 5(2-u)-u=10+4(u+1) equation: 



5(2-u)-u=10+4(u+1)

We move all terms to the left:

5(2-u)-u-(10+4(u+1))=0

We add all the numbers together, and all the variables

5(-1u+2)-u-(10+4(u+1))=0

We add all the numbers together, and all the variables

-1u+5(-1u+2)-(10+4(u+1))=0

We multiply parentheses

-1u-5u-(10+4(u+1))+10=0



We calculate terms in parentheses: -(10+4(u+1)), so:

10+4(u+1)

determiningTheFunctionDomain
4(u+1)+10

We multiply parentheses

4u+4+10

We add all the numbers together, and all the variables

4u+14

Back to the equation:

-(4u+14)



We add all the numbers together, and all the variables

-6u-(4u+14)+10=0

We get rid of parentheses

-6u-4u-14+10=0

We add all the numbers together, and all the variables

-10u-4=0

We move all terms containing u to the left, all other terms to the right

-10u=4

u=4/-10

u=-2/5

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