5(2-u)-u=2(u+1)-7

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Solution for 5(2-u)-u=2(u+1)-7 equation: 



5(2-u)-u=2(u+1)-7

We move all terms to the left:

5(2-u)-u-(2(u+1)-7)=0

We add all the numbers together, and all the variables

5(-1u+2)-u-(2(u+1)-7)=0

We add all the numbers together, and all the variables

-1u+5(-1u+2)-(2(u+1)-7)=0

We multiply parentheses

-1u-5u-(2(u+1)-7)+10=0



We calculate terms in parentheses: -(2(u+1)-7), so:

2(u+1)-7

We multiply parentheses

2u+2-7

We add all the numbers together, and all the variables

2u-5

Back to the equation:

-(2u-5)



We add all the numbers together, and all the variables

-6u-(2u-5)+10=0

We get rid of parentheses

-6u-2u+5+10=0

We add all the numbers together, and all the variables

-8u+15=0

We move all terms containing u to the left, all other terms to the right

-8u=-15

u=-15/-8

u=1+7/8

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