5(2-v)-4=4(2v-3)

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Solution for 5(2-v)-4=4(2v-3) equation:



5(2-v)-4=4(2v-3)
We move all terms to the left:
5(2-v)-4-(4(2v-3))=0
We add all the numbers together, and all the variables
5(-1v+2)-(4(2v-3))-4=0
We multiply parentheses
-5v-(4(2v-3))+10-4=0
We calculate terms in parentheses: -(4(2v-3)), so:
4(2v-3)
We multiply parentheses
8v-12
Back to the equation:
-(8v-12)
We add all the numbers together, and all the variables
-5v-(8v-12)+6=0
We get rid of parentheses
-5v-8v+12+6=0
We add all the numbers together, and all the variables
-13v+18=0
We move all terms containing v to the left, all other terms to the right
-13v=-18
v=-18/-13
v=1+5/13

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