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5(2-x)(3-x)=0
We add all the numbers together, and all the variables
5(-1x+2)(-1x+3)=0
We multiply parentheses ..
5(+x^2-3x-2x+6)=0
We multiply parentheses
5x^2-15x-10x+30=0
We add all the numbers together, and all the variables
5x^2-25x+30=0
a = 5; b = -25; c = +30;
Δ = b2-4ac
Δ = -252-4·5·30
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-5}{2*5}=\frac{20}{10} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+5}{2*5}=\frac{30}{10} =3 $
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