5(2-x)+3(x+2)=2(2x+2)-3(2+x)-3

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Solution for 5(2-x)+3(x+2)=2(2x+2)-3(2+x)-3 equation: 



5(2-x)+3(x+2)=2(2x+2)-3(2+x)-3

We move all terms to the left:

5(2-x)+3(x+2)-(2(2x+2)-3(2+x)-3)=0

We add all the numbers together, and all the variables

5(-1x+2)+3(x+2)-(2(2x+2)-3(x+2)-3)=0

We multiply parentheses

-5x+3x-(2(2x+2)-3(x+2)-3)+10+6=0



We calculate terms in parentheses: -(2(2x+2)-3(x+2)-3), so:

2(2x+2)-3(x+2)-3

We multiply parentheses

4x-3x+4-6-3

We add all the numbers together, and all the variables

x-5

Back to the equation:

-(x-5)



We add all the numbers together, and all the variables

-2x-(x-5)+16=0

We get rid of parentheses

-2x-x+5+16=0

We add all the numbers together, and all the variables

-3x+21=0

We move all terms containing x to the left, all other terms to the right

-3x=-21

x=-21/-3

x=+7

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