5(2-x)-(x+2)=6+8(x-5)

Solution for 5(2-x)-(x+2)=6+8(x-5) equation:

5(2-x)-(x+2)=6+8(x-5)

We move all terms to the left:

5(2-x)-(x+2)-(6+8(x-5))=0

We add all the numbers together, and all the variables

5(-1x+2)-(x+2)-(6+8(x-5))=0

We multiply parentheses

-5x-(x+2)-(6+8(x-5))+10=0

We get rid of parentheses

-5x-x-(6+8(x-5))-2+10=0


We calculate terms in parentheses: -(6+8(x-5)), so:

6+8(x-5)

determiningTheFunctionDomain
8(x-5)+6

We multiply parentheses

8x-40+6

We add all the numbers together, and all the variables

8x-34

Back to the equation:

-(8x-34)


We add all the numbers together, and all the variables

-6x-(8x-34)+8=0

We get rid of parentheses

-6x-8x+34+8=0

We add all the numbers together, and all the variables

-14x+42=0

We move all terms containing x to the left, all other terms to the right

-14x=-42

x=-42/-14

x=+3