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5(2-x)=3(2x-5)
We move all terms to the left:
5(2-x)-(3(2x-5))=0
We add all the numbers together, and all the variables
5(-1x+2)-(3(2x-5))=0
We multiply parentheses
-5x-(3(2x-5))+10=0
We calculate terms in parentheses: -(3(2x-5)), so:We get rid of parentheses
3(2x-5)
We multiply parentheses
6x-15
Back to the equation:
-(6x-15)
-5x-6x+15+10=0
We add all the numbers together, and all the variables
-11x+25=0
We move all terms containing x to the left, all other terms to the right
-11x=-25
x=-25/-11
x=2+3/11
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