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5(2-x)=3x-(x+4)
We move all terms to the left:
5(2-x)-(3x-(x+4))=0
We add all the numbers together, and all the variables
5(-1x+2)-(3x-(x+4))=0
We multiply parentheses
-5x-(3x-(x+4))+10=0
We calculate terms in parentheses: -(3x-(x+4)), so:We get rid of parentheses
3x-(x+4)
We get rid of parentheses
3x-x-4
We add all the numbers together, and all the variables
2x-4
Back to the equation:
-(2x-4)
-5x-2x+4+10=0
We add all the numbers together, and all the variables
-7x+14=0
We move all terms containing x to the left, all other terms to the right
-7x=-14
x=-14/-7
x=+2
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