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5(2/5x+2)=x-4
We move all terms to the left:
5(2/5x+2)-(x-4)=0
Domain of the equation: 5x+2)!=0We multiply parentheses
x∈R
10x-(x-4)+10=0
We get rid of parentheses
10x-x+4+10=0
We add all the numbers together, and all the variables
9x+14=0
We move all terms containing x to the left, all other terms to the right
9x=-14
x=-14/9
x=-1+5/9
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