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5(2/x+3)=35
We move all terms to the left:
5(2/x+3)-(35)=0
Domain of the equation: x+3)!=0We multiply parentheses
x∈R
10x+15-35=0
We add all the numbers together, and all the variables
10x-20=0
We move all terms containing x to the left, all other terms to the right
10x=20
x=20/10
x=2
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