5(20-3b)=105-8b+4(11-4b)

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Solution for 5(20-3b)=105-8b+4(11-4b) equation: 



5(20-3b)=105-8b+4(11-4b)

We move all terms to the left:

5(20-3b)-(105-8b+4(11-4b))=0

We add all the numbers together, and all the variables

5(-3b+20)-(105-8b+4(-4b+11))=0

We multiply parentheses

-15b-(105-8b+4(-4b+11))+100=0



We calculate terms in parentheses: -(105-8b+4(-4b+11)), so:

105-8b+4(-4b+11)

determiningTheFunctionDomain
-8b+4(-4b+11)+105

We multiply parentheses

-8b-16b+44+105

We add all the numbers together, and all the variables

-24b+149

Back to the equation:

-(-24b+149)



We get rid of parentheses

-15b+24b-149+100=0

We add all the numbers together, and all the variables

9b-49=0

We move all terms containing b to the left, all other terms to the right

9b=49

b=49/9

b=5+4/9

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