5(202+3.4)=5(y-2)+6y

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Solution for 5(202+3.4)=5(y-2)+6y equation: 



5(202+3.4)=5(y-2)+6y

We move all terms to the left:

5(202+3.4)-(5(y-2)+6y)=0

We add all the numbers together, and all the variables

-(5(y-2)+6y)+5(205.4)=0

We add all the numbers together, and all the variables

-(5(y-2)+6y)+1027=0



We calculate terms in parentheses: -(5(y-2)+6y), so:

5(y-2)+6y

We add all the numbers together, and all the variables

6y+5(y-2)

We multiply parentheses

6y+5y-10

We add all the numbers together, and all the variables

11y-10

Back to the equation:

-(11y-10)



We get rid of parentheses

-11y+10+1027=0

We add all the numbers together, and all the variables

-11y+1037=0

We move all terms containing y to the left, all other terms to the right

-11y=-1037

y=-1037/-11

y=94+3/11

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