5(21/2+c)=20

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Solution for 5(21/2+c)=20 equation: 



5(21/2+c)=20

We move all terms to the left:

5(21/2+c)-(20)=0



Domain of the equation: 2+c)!=0

We move all terms containing c to the left, all other terms to the right

c)!=-2

c!=-2/1

c!=-2

c∈R



We add all the numbers together, and all the variables

5(+c+21/2)-20=0

We multiply parentheses

5c-20+21/2*5=0

We multiply all the terms by the denominator


5c*2*5+21-20*2*5=0

We add all the numbers together, and all the variables

5c*2*5-179=0

Wy multiply elements

50c*5-179=0

Wy multiply elements

250c-179=0

We move all terms containing c to the left, all other terms to the right

250c=179

c=179/250

c=179/250

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