5(23-n)=4(n-25)

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Solution for 5(23-n)=4(n-25) equation: 



5(23-n)=4(n-25)

We move all terms to the left:

5(23-n)-(4(n-25))=0

We add all the numbers together, and all the variables

5(-1n+23)-(4(n-25))=0

We multiply parentheses

-5n-(4(n-25))+115=0



We calculate terms in parentheses: -(4(n-25)), so:

4(n-25)

We multiply parentheses

4n-100

Back to the equation:

-(4n-100)



We get rid of parentheses

-5n-4n+100+115=0

We add all the numbers together, and all the variables

-9n+215=0

We move all terms containing n to the left, all other terms to the right

-9n=-215

n=-215/-9

n=23+8/9

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