5(25-1)-3(3+2);s=4

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Solution for 5(25-1)-3(3+2);s=4 equation: 



5(25-1)-3(3+2)s=4

We move all terms to the left:

5(25-1)-3(3+2)s-(4)=0

determiningTheFunctionDomain
-3(3+2)s-4+5(25-1)=0

We add all the numbers together, and all the variables

-35s-4+524=0

We add all the numbers together, and all the variables

-35s+520=0

We move all terms containing s to the left, all other terms to the right

-35s=-520

s=-520/-35

s=14+6/7

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