5(25-5k)=21-3(k-4)

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Solution for 5(25-5k)=21-3(k-4) equation: 



5(25-5k)=21-3(k-4)

We move all terms to the left:

5(25-5k)-(21-3(k-4))=0

We add all the numbers together, and all the variables

5(-5k+25)-(21-3(k-4))=0

We multiply parentheses

-25k-(21-3(k-4))+125=0



We calculate terms in parentheses: -(21-3(k-4)), so:

21-3(k-4)

determiningTheFunctionDomain
-3(k-4)+21

We multiply parentheses

-3k+12+21

We add all the numbers together, and all the variables

-3k+33

Back to the equation:

-(-3k+33)



We get rid of parentheses

-25k+3k-33+125=0

We add all the numbers together, and all the variables

-22k+92=0

We move all terms containing k to the left, all other terms to the right

-22k=-92

k=-92/-22

k=4+2/11

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