5(27/5y)+2y=16

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Solution for 5(27/5y)+2y=16 equation:



5(27/5y)+2y=16
We move all terms to the left:
5(27/5y)+2y-(16)=0
Domain of the equation: 5y)!=0
y!=0/1
y!=0
y∈R
We add all the numbers together, and all the variables
5(+27/5y)+2y-16=0
We add all the numbers together, and all the variables
2y+5(+27/5y)-16=0
We multiply parentheses
2y+135y-16=0
We add all the numbers together, and all the variables
137y-16=0
We move all terms containing y to the left, all other terms to the right
137y=16
y=16/137
y=16/137

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