5(2X-3)=(x-2)+5

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Solution for 5(2X-3)=(x-2)+5 equation:



5(2X-3)=(X-2)+5
We move all terms to the left:
5(2X-3)-((X-2)+5)=0
We multiply parentheses
10X-((X-2)+5)-15=0
We calculate terms in parentheses: -((X-2)+5), so:
(X-2)+5
We get rid of parentheses
X-2+5
We add all the numbers together, and all the variables
X+3
Back to the equation:
-(X+3)
We get rid of parentheses
10X-X-3-15=0
We add all the numbers together, and all the variables
9X-18=0
We move all terms containing X to the left, all other terms to the right
9X=18
X=18/9
X=2

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