5(2a+1)-4a=3(5a-4)-1

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Solution for 5(2a+1)-4a=3(5a-4)-1 equation: 



5(2a+1)-4a=3(5a-4)-1

We move all terms to the left:

5(2a+1)-4a-(3(5a-4)-1)=0

We add all the numbers together, and all the variables

-4a+5(2a+1)-(3(5a-4)-1)=0

We multiply parentheses

-4a+10a-(3(5a-4)-1)+5=0



We calculate terms in parentheses: -(3(5a-4)-1), so:

3(5a-4)-1

We multiply parentheses

15a-12-1

We add all the numbers together, and all the variables

15a-13

Back to the equation:

-(15a-13)



We add all the numbers together, and all the variables

6a-(15a-13)+5=0

We get rid of parentheses

6a-15a+13+5=0

We add all the numbers together, and all the variables

-9a+18=0

We move all terms containing a to the left, all other terms to the right

-9a=-18

a=-18/-9

a=+2

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