5(2a+1)=6(a-5)

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Solution for 5(2a+1)=6(a-5) equation: 



5(2a+1)=6(a-5)

We move all terms to the left:

5(2a+1)-(6(a-5))=0

We multiply parentheses

10a-(6(a-5))+5=0



We calculate terms in parentheses: -(6(a-5)), so:

6(a-5)

We multiply parentheses

6a-30

Back to the equation:

-(6a-30)



We get rid of parentheses

10a-6a+30+5=0

We add all the numbers together, and all the variables

4a+35=0

We move all terms containing a to the left, all other terms to the right

4a=-35

a=-35/4

a=-8+3/4

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