5(2a+3)+3(a-4)=8(a-2)-1

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Solution for 5(2a+3)+3(a-4)=8(a-2)-1 equation: 



5(2a+3)+3(a-4)=8(a-2)-1

We move all terms to the left:

5(2a+3)+3(a-4)-(8(a-2)-1)=0

We multiply parentheses

10a+3a-(8(a-2)-1)+15-12=0



We calculate terms in parentheses: -(8(a-2)-1), so:

8(a-2)-1

We multiply parentheses

8a-16-1

We add all the numbers together, and all the variables

8a-17

Back to the equation:

-(8a-17)



We add all the numbers together, and all the variables

13a-(8a-17)+3=0

We get rid of parentheses

13a-8a+17+3=0

We add all the numbers together, and all the variables

5a+20=0

We move all terms containing a to the left, all other terms to the right

5a=-20

a=-20/5

a=-4

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