5(2b+1)-3(b+1)=7b+5

Solution for 5(2b+1)-3(b+1)=7b+5 equation:

Simplifying
5(2b + 1) + -3(b + 1) = 7b + 5

Reorder the terms:
5(1 + 2b) + -3(b + 1) = 7b + 5
(1 * 5 + 2b * 5) + -3(b + 1) = 7b + 5
(5 + 10b) + -3(b + 1) = 7b + 5

Reorder the terms:
5 + 10b + -3(1 + b) = 7b + 5
5 + 10b + (1 * -3 + b * -3) = 7b + 5
5 + 10b + (-3 + -3b) = 7b + 5

Reorder the terms:
5 + -3 + 10b + -3b = 7b + 5

Combine like terms: 5 + -3 = 2
2 + 10b + -3b = 7b + 5

Combine like terms: 10b + -3b = 7b
2 + 7b = 7b + 5

Reorder the terms:
2 + 7b = 5 + 7b

Add '-7b' to each side of the equation.
2 + 7b + -7b = 5 + 7b + -7b

Combine like terms: 7b + -7b = 0
2 + 0 = 5 + 7b + -7b
2 = 5 + 7b + -7b

Combine like terms: 7b + -7b = 0
2 = 5 + 0
2 = 5

Solving
2 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.