5(2b+1)=36

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Solution for 5(2b+1)=36 equation: 



5(2b+1)=36

We move all terms to the left:

5(2b+1)-(36)=0

We multiply parentheses

10b+5-36=0

We add all the numbers together, and all the variables

10b-31=0

We move all terms containing b to the left, all other terms to the right

10b=31

b=31/10

b=3+1/10

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