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5(2b-1)6b=2
We move all terms to the left:
5(2b-1)6b-(2)=0
We multiply parentheses
60b^2-30b-2=0
a = 60; b = -30; c = -2;
Δ = b2-4ac
Δ = -302-4·60·(-2)
Δ = 1380
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1380}=\sqrt{4*345}=\sqrt{4}*\sqrt{345}=2\sqrt{345}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{345}}{2*60}=\frac{30-2\sqrt{345}}{120} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{345}}{2*60}=\frac{30+2\sqrt{345}}{120} $
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