5(2b-3)+4=-3(b+2)+8b

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Solution for 5(2b-3)+4=-3(b+2)+8b equation: 



5(2b-3)+4=-3(b+2)+8b

We move all terms to the left:

5(2b-3)+4-(-3(b+2)+8b)=0

We multiply parentheses

10b-(-3(b+2)+8b)-15+4=0



We calculate terms in parentheses: -(-3(b+2)+8b), so:

-3(b+2)+8b

We add all the numbers together, and all the variables

8b-3(b+2)

We multiply parentheses

8b-3b-6

We add all the numbers together, and all the variables

5b-6

Back to the equation:

-(5b-6)



We add all the numbers together, and all the variables

10b-(5b-6)-11=0

We get rid of parentheses

10b-5b+6-11=0

We add all the numbers together, and all the variables

5b-5=0

We move all terms containing b to the left, all other terms to the right

5b=5

b=5/5

b=1

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