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5(2b-3)=(12b-17)
We move all terms to the left:
5(2b-3)-((12b-17))=0
We multiply parentheses
10b-((12b-17))-15=0
We calculate terms in parentheses: -((12b-17)), so:We get rid of parentheses
(12b-17)
We get rid of parentheses
12b-17
Back to the equation:
-(12b-17)
10b-12b+17-15=0
We add all the numbers together, and all the variables
-2b+2=0
We move all terms containing b to the left, all other terms to the right
-2b=-2
b=-2/-2
b=1
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