5(2c+1)=3(3c-2)

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Solution for 5(2c+1)=3(3c-2) equation: 



5(2c+1)=3(3c-2)

We move all terms to the left:

5(2c+1)-(3(3c-2))=0

We multiply parentheses

10c-(3(3c-2))+5=0



We calculate terms in parentheses: -(3(3c-2)), so:

3(3c-2)

We multiply parentheses

9c-6

Back to the equation:

-(9c-6)



We get rid of parentheses

10c-9c+6+5=0

We add all the numbers together, and all the variables

c+11=0

We move all terms containing c to the left, all other terms to the right

c=-11

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