5(2c+3)-5=-2(c+1)

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Solution for 5(2c+3)-5=-2(c+1) equation: 



5(2c+3)-5=-2(c+1)

We move all terms to the left:

5(2c+3)-5-(-2(c+1))=0

We multiply parentheses

10c-(-2(c+1))+15-5=0



We calculate terms in parentheses: -(-2(c+1)), so:

-2(c+1)

We multiply parentheses

-2c-2

Back to the equation:

-(-2c-2)



We add all the numbers together, and all the variables

10c-(-2c-2)+10=0

We get rid of parentheses

10c+2c+2+10=0

We add all the numbers together, and all the variables

12c+12=0

We move all terms containing c to the left, all other terms to the right

12c=-12

c=-12/12

c=-1

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