5(2c+4)+10=-20

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Solution for 5(2c+4)+10=-20 equation: 



5(2c+4)+10=-20

We move all terms to the left:

5(2c+4)+10-(-20)=0

We add all the numbers together, and all the variables

5(2c+4)+30=0

We multiply parentheses

10c+20+30=0

We add all the numbers together, and all the variables

10c+50=0

We move all terms containing c to the left, all other terms to the right

10c=-50

c=-50/10

c=-5

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