5(2c+6)=-4(-2c-5)+3c

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Solution for 5(2c+6)=-4(-2c-5)+3c equation: 



5(2c+6)=-4(-2c-5)+3c

We move all terms to the left:

5(2c+6)-(-4(-2c-5)+3c)=0

We multiply parentheses

10c-(-4(-2c-5)+3c)+30=0



We calculate terms in parentheses: -(-4(-2c-5)+3c), so:

-4(-2c-5)+3c

We add all the numbers together, and all the variables

3c-4(-2c-5)

We multiply parentheses

3c+8c+20

We add all the numbers together, and all the variables

11c+20

Back to the equation:

-(11c+20)



We get rid of parentheses

10c-11c-20+30=0

We add all the numbers together, and all the variables

-1c+10=0

We move all terms containing c to the left, all other terms to the right

-c=-10

c=-10/-1

c=+10

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