5(2c+7)+3c=7(c+4)

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Solution for 5(2c+7)+3c=7(c+4) equation: 



5(2c+7)+3c=7(c+4)

We move all terms to the left:

5(2c+7)+3c-(7(c+4))=0

We add all the numbers together, and all the variables

3c+5(2c+7)-(7(c+4))=0

We multiply parentheses

3c+10c-(7(c+4))+35=0



We calculate terms in parentheses: -(7(c+4)), so:

7(c+4)

We multiply parentheses

7c+28

Back to the equation:

-(7c+28)



We add all the numbers together, and all the variables

13c-(7c+28)+35=0

We get rid of parentheses

13c-7c-28+35=0

We add all the numbers together, and all the variables

6c+7=0

We move all terms containing c to the left, all other terms to the right

6c=-7

c=-7/6

c=-1+1/6

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