5(2c+7)-4c=7(c+4)

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Solution for 5(2c+7)-4c=7(c+4) equation: 



5(2c+7)-4c=7(c+4)

We move all terms to the left:

5(2c+7)-4c-(7(c+4))=0

We add all the numbers together, and all the variables

-4c+5(2c+7)-(7(c+4))=0

We multiply parentheses

-4c+10c-(7(c+4))+35=0



We calculate terms in parentheses: -(7(c+4)), so:

7(c+4)

We multiply parentheses

7c+28

Back to the equation:

-(7c+28)



We add all the numbers together, and all the variables

6c-(7c+28)+35=0

We get rid of parentheses

6c-7c-28+35=0

We add all the numbers together, and all the variables

-1c+7=0

We move all terms containing c to the left, all other terms to the right

-c=-7

c=-7/-1

c=+7

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