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5(2c+7)=7(c+5)
We move all terms to the left:
5(2c+7)-(7(c+5))=0
We multiply parentheses
10c-(7(c+5))+35=0
We calculate terms in parentheses: -(7(c+5)), so:We get rid of parentheses
7(c+5)
We multiply parentheses
7c+35
Back to the equation:
-(7c+35)
10c-7c-35+35=0
We add all the numbers together, and all the variables
3c=0
c=0/3
c=0
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