5(2c-)=(2c+11)

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Solution for 5(2c-)=(2c+11) equation: 



5(2c-)=(2c+11)

We move all terms to the left:

5(2c-)-((2c+11))=0

We add all the numbers together, and all the variables

5(+2c)-((2c+11))=0

We multiply parentheses

10c-((2c+11))=0



We calculate terms in parentheses: -((2c+11)), so:

(2c+11)

We get rid of parentheses

2c+11

Back to the equation:

-(2c+11)



We get rid of parentheses

10c-2c-11=0

We add all the numbers together, and all the variables

8c-11=0

We move all terms containing c to the left, all other terms to the right

8c=11

c=11/8

c=1+3/8

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