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5(2c-)=(2c+11)
We move all terms to the left:
5(2c-)-((2c+11))=0
We add all the numbers together, and all the variables
5(+2c)-((2c+11))=0
We multiply parentheses
10c-((2c+11))=0
We calculate terms in parentheses: -((2c+11)), so:We get rid of parentheses
(2c+11)
We get rid of parentheses
2c+11
Back to the equation:
-(2c+11)
10c-2c-11=0
We add all the numbers together, and all the variables
8c-11=0
We move all terms containing c to the left, all other terms to the right
8c=11
c=11/8
c=1+3/8
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