5(2c-1)=35

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Solution for 5(2c-1)=35 equation: 



5(2c-1)=35

We move all terms to the left:

5(2c-1)-(35)=0

We multiply parentheses

10c-5-35=0

We add all the numbers together, and all the variables

10c-40=0

We move all terms containing c to the left, all other terms to the right

10c=40

c=40/10

c=4

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