5(2c-12)+21=2c+41

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Solution for 5(2c-12)+21=2c+41 equation:


Simplifying
5(2c + -12) + 21 = 2c + 41

Reorder the terms:
5(-12 + 2c) + 21 = 2c + 41
(-12 * 5 + 2c * 5) + 21 = 2c + 41
(-60 + 10c) + 21 = 2c + 41

Reorder the terms:
-60 + 21 + 10c = 2c + 41

Combine like terms: -60 + 21 = -39
-39 + 10c = 2c + 41

Reorder the terms:
-39 + 10c = 41 + 2c

Solving
-39 + 10c = 41 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
-39 + 10c + -2c = 41 + 2c + -2c

Combine like terms: 10c + -2c = 8c
-39 + 8c = 41 + 2c + -2c

Combine like terms: 2c + -2c = 0
-39 + 8c = 41 + 0
-39 + 8c = 41

Add '39' to each side of the equation.
-39 + 39 + 8c = 41 + 39

Combine like terms: -39 + 39 = 0
0 + 8c = 41 + 39
8c = 41 + 39

Combine like terms: 41 + 39 = 80
8c = 80

Divide each side by '8'.
c = 10

Simplifying
c = 10

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