5(2c-3)=3(3c-5)=

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Solution for 5(2c-3)=3(3c-5)= equation: 



5(2c-3)=3(3c-5)=

We move all terms to the left:

5(2c-3)-(3(3c-5))=0

We multiply parentheses

10c-(3(3c-5))-15=0



We calculate terms in parentheses: -(3(3c-5)), so:

3(3c-5)

We multiply parentheses

9c-15

Back to the equation:

-(9c-15)



We get rid of parentheses

10c-9c+15-15=0

We add all the numbers together, and all the variables

c=0

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