5(2c-3)=3(4c+7)

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Solution for 5(2c-3)=3(4c+7) equation: 



5(2c-3)=3(4c+7)

We move all terms to the left:

5(2c-3)-(3(4c+7))=0

We multiply parentheses

10c-(3(4c+7))-15=0



We calculate terms in parentheses: -(3(4c+7)), so:

3(4c+7)

We multiply parentheses

12c+21

Back to the equation:

-(12c+21)



We get rid of parentheses

10c-12c-21-15=0

We add all the numbers together, and all the variables

-2c-36=0

We move all terms containing c to the left, all other terms to the right

-2c=36

c=36/-2

c=-18

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