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5(2c-4)=10c-0
We move all terms to the left:
5(2c-4)-(10c-0)=0
We add all the numbers together, and all the variables
5(2c-4)-(+10c)=0
We multiply parentheses
10c-(+10c)-20=0
We get rid of parentheses
10c-10c-20=0
We add all the numbers together, and all the variables
-20!=0
There is no solution for this equation
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